Derivative Rules - Multi Chain Natural Exponential Trigonometric to Derivative

Question

Find the derivative f'(x) using the chain, natural exponential, and trigonometric rules.

$$f(x) = (2e^{x} + 2\cos(x))^{-2}$$

Accepted Answer

$$f'(x) = -2(2e^{x} + 2\cos(x))^{-3} \cdot \left(2e^{x} - 2\sin(x)\right)$$

Answer

$$f'(x) = -2(2e^{x} + 2\cos(x))^{-2} \cdot \left(2e^{x} - 2\sin(x)\right)$$

Answer

$$f'(x) = -2(2e^{x} + 2\cos(x))^{-3}$$

Answer

$$f'(x) = (2e^{x} + 2\cos(x))^{-3} \cdot \left(2e^{x} - 2\sin(x)\right)$$

Practice: Derivative Rules - Multi Chain Natural Exponential Trigonometric to Derivative