Question

Find the derivative f'(x) using the product, chain, and trigonometric rules.

$$\begin{array}{l} \displaystyle \frac{d}{dx}\cos(x) = -\sin(x) \[12pt] \displaystyle f(x) = (3x - 5)^{2}\left(4\cos(x)\right) \end{array}$$

Accepted Answer

$$f'(x) = 6(3x - 5)\left(4\cos(x)\right) + (3x - 5)^{2}\left(-4\sin(x)\right)$$

Answer

$$f'(x) = (3x - 5)^{2}\left(-4\sin(x)\right)$$

Answer

$$f'(x) = 6(3x - 5)\left(4\cos(x)\right)$$

Answer

$$f'(x) = 6(3x - 5)\left(-4\sin(x)\right)$$

Derivative Rules - Multi Chain Product Trigonometric (with Rule) to Derivative