Derivative Rules - Product Rule Negative Fractional Powers to Derivative

Question

Find the derivative f'(x) using the product rule.

$$f(x) = (3x^{-\frac{1}{2}} - 7)(2x^{2} - 5)$$

Accepted Answer

$$f'(x) = (-\frac{3}{2}x^{-\frac{3}{2}})(2x^{2} - 5) + (3x^{-\frac{1}{2}} - 7)(4x)$$

Answer

$$f'(x) = (-\frac{3}{2}x^{-\frac{3}{2}})(2x^{2} - 5) - (3x^{-\frac{1}{2}} - 7)(4x)$$

Answer

$$f'(x) = (-\frac{3}{2}x^{-\frac{3}{2}})(2x^{2} - 5)$$

Answer

$$f'(x) = (-\frac{3}{2}x^{-\frac{3}{2}})(4x)$$

Practice: Derivative Rules - Product Rule Negative Fractional Powers to Derivative