Question

The graph shows y=9+1x for 0<=x<=3. What does its surface-area integral about the x-axis measure?

Accepted Answer

$$\begin{aligned}&	ext{The lateral area swept out by the segment}\ &	ext{is }63\pi\sqrt{2}\,	ext{square units.}\end{aligned}$$

Answer

$$\begin{aligned}&	ext{The region under the line has area}\ &	ext{of }63\pi\sqrt{2}\,	ext{square units.}\end{aligned}$$

Answer

$$\begin{aligned}&	ext{The volume of the solid}\ &	ext{is }63\pi\sqrt{2}\,	ext{cubic units.}\end{aligned}$$

Answer

$$\begin{aligned}&	ext{The arc length of the segment}\ &	ext{is }63\pi\sqrt{2}\,	ext{units.}\end{aligned}$$

Practice: Integration - Interpret Surface Area Graph