Question

The shaded region lies between the right-hand curve $x_{\mathrm{right}}(y)$ and left-hand curve $x_{\mathrm{left}}(y)$ from $y=0$ to $y=5$. Which integral gives its area?

Accepted Answer

$$\int_{0}^{5} (x_{\mathrm{right}}(y)-x_{\mathrm{left}}(y))\,dy$$

Answer

$$\int_{0}^{5} (x_{\mathrm{left}}(y)-x_{\mathrm{right}}(y))\,dy$$

Answer

$$\int_{0}^{5} (x_{\mathrm{right}}(y)+x_{\mathrm{left}}(y))\,dy$$

Answer

$$\int_{0}^{5} x_{\mathrm{right}}(y)\,dy$$

Practice: Integration - Curves Graph to Area Setup in y

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Practice:

Integration - Curves Graph to Area Setup in y