Question

Which expression finds the average rate over the interval below?

$$\begin{aligned}f(x)&=15x^{2}+3,\quad 0\le x\le 6\f_{\mathrm{avg}}&=\frac{1}{6}\int_0^{6} f(x)\,dx\end{aligned}$$

Accepted Answer

$$\frac{1}{6}\int_{0}^{6} (15x^{2}+3)\,dx$$

Answer

$$\int_{0}^{6} (15x^{2}+3)\,dx$$

Answer

$$\frac{f(6)-f(0)}{6}$$

Answer

$$\frac{f(0)+f(6)}{2}$$

Practice: Integration - Function Context to Average Value Setup