Question

For x where the denominator is nonzero, which step sets up the general antiderivative of the expression below?

$$\frac{1}{x-9}$$

Accepted Answer

$$\begin{aligned}&	ext{identify }f(x)=x-9,\;f'(x)=1\ &	ext{use }\ln|x-9|+C\end{aligned}$$

Answer

$$\begin{aligned}&	ext{identify }f(x)=x-9,\;f'(x)=1\ &	ext{use }\ln|x-9|\end{aligned}$$

Answer

$$\begin{aligned}&	ext{identify }f(x)=x-9,\;f'(x)=1\ &	ext{use }\frac{1}{x-9}+C\end{aligned}$$

Answer

$$\begin{aligned}&	ext{identify }f(x)=x-9,\;f'(x)=1\ &	ext{use }\ln|1|+C\end{aligned}$$

Practice: Integration - Reciprocal Intermediate Step