Probability Union, Intersection, Complement - Word Problem Counts and Percents to Formula

Question

Let A be the dog group and B be the cat group. Which expression gives the number of households who are in neither group?

In a group of 100 households, 44% own a dog, 19 own a cat, and 10% own both.

Accepted Answer

$$N - n(A) - n(B) + n(A \cap B)$$

Answer

$$N - n(A) - n(B) - n(A \cap B)$$

Answer

$$n(A) + n(B) - n(A \cap B)$$

Answer

$$N - n(A) - n(B)$$

Practice: Probability Union, Intersection, Complement - Word Problem Counts and Percents to Formula