Trigonometry Identity Solve - Select a Cosine Double-Angle Form (Identity Shown)

Question

Solve the trigonometric equation for x in the given domain.

$$\begin{gathered} \cos^2(x) - \sin^2(x) = -\frac{\sqrt{3}}{2} \ 	ext{for } 0 \le x < 2\pi \ ule{14em}{0.4pt} \ 	ext{using } \cos(2x) = \cos^2 x - \sin^2 x = 1 - 2\sin^2 x = 2\cos^2 x - 1 \end{gathered}$$

Accepted Answer

$$x = \frac{5\pi}{12} 	ext{ or } x = \frac{7\pi}{12} 	ext{ or } x = \frac{17\pi}{12} 	ext{ or } x = \frac{19\pi}{12}$$

Answer

$$x = \frac{5\pi}{12} 	ext{ or } x = \frac{7\pi}{12} 	ext{ or } x = \frac{17\pi}{12}$$

Answer

$$x = \frac{5\pi}{12}$$

Answer

$$x = \frac{5\pi}{12} 	ext{ or } x = \frac{7\pi}{12} 	ext{ or } x = \frac{11\pi}{12} 	ext{ or } x = \frac{17\pi}{12} 	ext{ or } x = \frac{19\pi}{12}$$

Trigonometry Identity Solve - Select a Cosine Double-Angle Form (Identity Shown)

Practice:

Trigonometry Identity Solve - Select a Cosine Double-Angle Form (Identity Shown)