Skill: Approximate irrational numbers

Explanation and Free Practice Resources

An irrational number is understood as a real number whose decimal expansion is nonterminating and nonrepeating, and it can be located and compared by finding rational bounds or decimal approximations—for example, placing 2\sqrt{2} between 1.411.41 and 1.421.42 and rounding it to a specified place value. The approximation is not the irrational number itself; using bounds, number-line position, and appropriate precision supports calculations involving radicals, measurement, and geometry, without requiring formal proofs of irrationality or advanced approximation methods.

Detailed Explanation: Approximate irrational numbers

An irrational number cannot be written as a terminating or repeating decimal. To approximate one, find two nearby rational numbers that bound it, then round to the requested place value.

Example: Approximate 2\sqrt{2} to the nearest hundredth

We know:

12=1and22=41^2=1 \quad\text{and}\quad 2^2=4

so 2\sqrt{2} is between 11 and 22.

  1. Try hundredths:
1.412=1.98811.41^2=1.9881

and

1.422=2.01641.42^2=2.0164

Since 1.9881<2<2.01641.9881<2<2.0164, it follows that

1.41<2<1.42.1.41<\sqrt{2}<1.42.
  1. To decide whether to round to 1.411.41 or 1.421.42, check the thousandths:
1.4142=1.9993961.414^2=1.999396

and

1.4152=2.002225.1.415^2=2.002225.

Therefore,

1.414<2<1.415.1.414<\sqrt{2}<1.415.
  1. The number is less than 1.4151.415, so it rounds down to the nearest hundredth:
2≈1.41\boxed{\sqrt{2}\approx 1.41}

The symbol ≈\approx means “approximately equal to.” The decimal 1.411.41 is an approximation, not the exact value of the irrational number 2\sqrt{2}.

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Number Types (Irrational) - Between X and Y - Positive Square Roots, Cube Roots, Pi


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