Skill: Calculate sums of arithmetic series

Explanation and Free Practice Resources

A finite arithmetic series is the sum of terms in an arithmetic sequence, whose consecutive terms differ by a constant common difference. The sum can be determined by pairing first and last terms, using Sn=n2(a1+an)=n2[2a1+(n−1)d]S_n=\frac{n}{2}(a_1+a_n)=\frac{n}{2}[2a_1+(n-1)d], while distinguishing the number of terms from the value of a term; infinite-series convergence and more advanced generalizations are outside this scope.

Detailed Explanation: Calculate sums of arithmetic series

An arithmetic series is the sum of the terms of an arithmetic sequence. The difference between consecutive terms is constant.

To calculate its sum, use

Sn=n2(a1+an),S_n=\frac{n}{2}(a_1+a_n),

where:

  • SnS_n is the sum,
  • nn is the number of terms,
  • a1a_1 is the first term,
  • ana_n is the last term.

Example

Find the sum

7+11+15+⋯+63.7+11+15+\cdots+63.

Step 1: Identify the values.

The first term is

a1=7,a_1=7,

and the common difference is

d=11−7=4.d=11-7=4.

The last term is

an=63.a_n=63.

We still need to find nn, the number of terms.

Step 2: Find the number of terms.

Use the formula for the nnth term:

an=a1+(n−1)d.a_n=a_1+(n-1)d.

Substitute the known values:

63=7+(n−1)(4).63=7+(n-1)(4).

Solve:

56=4(n−1)56=4(n-1) 14=n−114=n-1 n=15.n=15.

There are 1515 terms. Notice that nn is a count of terms, not the value of the last term.

Step 3: Calculate the sum.

Use

Sn=n2(a1+an).S_n=\frac{n}{2}(a_1+a_n).

Thus,

S15=152(7+63)S_{15}=\frac{15}{2}(7+63) S15=152(70)S_{15}=\frac{15}{2}(70) S15=525.\boxed{S_{15}=525}.

So,

7+11+15+⋯+63=525.7+11+15+\cdots+63=525.

Learn by doing: Calculate sums of arithmetic series

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Sums - Series of Integers 1 to N - Addition to Sum


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