Skill: Condense logarithmic expressions

Explanation and Free Practice Resources

Condensing logarithmic expressions means reversing the product, quotient, and power properties to rewrite sums, differences, and coefficients of logarithms with the same base as one logarithm, such as log⁡bM+log⁡bN=log⁡b(MN)\log_b M+\log_b N=\log_b(MN) and klog⁡bM=log⁡b(Mk)k\log_b M=\log_b(M^k). The reasoning requires preserving equivalent values while ensuring every logarithm’s argument is positive and avoiding the misconception that a sum of logarithms equals the logarithm of a sum; this structure supports solving logarithmic equations.

Detailed Explanation: Condense logarithmic expressions

To condense logarithms, reverse the logarithm properties:

  • klog⁡bM=log⁡b(Mk)k\log_b M=\log_b(M^k)
  • log⁡bM+log⁡bN=log⁡b(MN)\log_b M+\log_b N=\log_b(MN)
  • log⁡bM−log⁡bN=log⁡b(MN)\log_b M-\log_b N=\log_b\left(\frac{M}{N}\right)

The logarithms must have the same base, and every argument must be positive. Also, a sum of logarithms becomes the logarithm of a product, not a sum.

Example

Condense the expression:

2log⁡3x+log⁡3(x−1)−log⁡352\log_3 x+\log_3(x-1)-\log_3 5

Assume x>1x>1, so both xx and x−1x-1 are positive.

Step 1: Move the coefficient into the first logarithm as an exponent.

2log⁡3x=log⁡3(x2)2\log_3 x=\log_3(x^2)

Now the expression is

log⁡3(x2)+log⁡3(x−1)−log⁡35\log_3(x^2)+\log_3(x-1)-\log_3 5

Step 2: Combine the sum using the product property.

log⁡3(x2)+log⁡3(x−1)=log⁡3(x2(x−1))\log_3(x^2)+\log_3(x-1)=\log_3\bigl(x^2(x-1)\bigr)

So we have

log⁡3(x2(x−1))−log⁡35\log_3\bigl(x^2(x-1)\bigr)-\log_3 5

Step 3: Combine the difference using the quotient property.

log⁡3(x2(x−1)5)\boxed{\log_3\left(\frac{x^2(x-1)}{5}\right)}

Thus,

2log⁡3x+log⁡3(x−1)−log⁡35=log⁡3(x2(x−1)5).2\log_3 x+\log_3(x-1)-\log_3 5 =\log_3\left(\frac{x^2(x-1)}{5}\right).

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Logarithms - Product Property - Sum to Product (Variables)


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