The relationship ab=c⟺loga(c)=b is understood for a>0, a=1, and c>0: the base remains the logarithm’s base, the exponent becomes the logarithm’s value, and the exponential result becomes its argument. This inverse relationship supports interpreting and solving exponential and logarithmic equations; the scope is limited to real-valued expressions and does not include complex logarithms or more advanced logarithmic generalizations.
Detailed Explanation: Convert between exponential and logarithmic form
The exponential and logarithmic forms of the same statement are connected by
ab=c⟺loga(c)=b.
To convert from exponential form to logarithmic form:
Keep the base the same.
Make the result the argument of the logarithm.
Make the exponent the value of the logarithm.
Example
Convert
25=32
to logarithmic form.
The base is 2, so the logarithm’s base is also 2.
The result is 32, so 32 goes inside the logarithm.
The exponent is 5, so 5 goes on the other side of the equation.
Therefore,
25=32⟺log2(32)=5.
The reverse conversion follows the same relationship:
log2(32)=5⟺25=32.
This relationship applies when a>0, a=1, and c>0.
Learn by doing: Convert between exponential and logarithmic form
Click a topic below to practice the foundational skills you'll need, learn the steps, or master this skill
Practice with unlimited practice problems
Practice:
Logarithms - Convert Exponent to Logarithm - Fraction Value