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Convert between exponential and logarithmic form

The relationship ab=cloga(c)=ba^b=c \Longleftrightarrow \log_a(c)=b is understood for a>0a>0, a1a\ne1, and c>0c>0: the base remains the logarithm’s base, the exponent becomes the logarithm’s value, and the exponential result becomes its argument. This inverse relationship supports interpreting and solving exponential and logarithmic equations; the scope is limited to real-valued expressions and does not include complex logarithms or more advanced logarithmic generalizations.

Detailed Explanation: Convert between exponential and logarithmic form

The exponential and logarithmic forms of the same statement are connected by

ab=cloga(c)=b.a^b=c \quad\Longleftrightarrow\quad \log_a(c)=b.

To convert from exponential form to logarithmic form:

  • Keep the base the same.
  • Make the result the argument of the logarithm.
  • Make the exponent the value of the logarithm.

Example

Convert

25=322^5=32

to logarithmic form.

  1. The base is 22, so the logarithm’s base is also 22.
  2. The result is 3232, so 3232 goes inside the logarithm.
  3. The exponent is 55, so 55 goes on the other side of the equation.

Therefore,

25=32log2(32)=5.2^5=32 \quad\Longleftrightarrow\quad \log_2(32)=5.

The reverse conversion follows the same relationship:

log2(32)=525=32.\log_2(32)=5 \quad\Longleftrightarrow\quad 2^5=32.

This relationship applies when a>0a>0, a1a\ne1, and c>0c>0.

Learn by doing: Convert between exponential and logarithmic form

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Logarithms - Convert Exponent to Logarithm - Fraction Value


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