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Convert between exponential and logarithmic form

The equivalence ab=c    loga(c)=ba^b=c \iff \log_a(c)=b expresses logarithms as the inverse operation of exponentiation: the logarithm gives the exponent to which a positive base must be raised to produce a given positive value. This includes translating among exponential equations, logarithmic equations, and function representations while respecting a>0a>0, a1a\ne1, and c>0c>0, and supports solving exponential and logarithmic equations; complex logarithms and more abstract extensions are not included.

Detailed Explanation: Convert between exponential and logarithmic form

An exponential equation and a logarithmic equation can say the same thing in two different ways:

ab=cloga(c)=ba^b=c \quad\Longleftrightarrow\quad \log_a(c)=b

The base stays the same, the result of the exponentiation becomes the logarithm’s argument, and the exponent becomes the logarithm’s value.

For these equations, the conditions are

a>0,a1,c>0.a>0,\qquad a\ne 1,\qquad c>0.

Worked example

Rewrite the exponential equation

25=322^5=32

in logarithmic form.

Step 1: Identify the parts.

In 25=322^5=32:

  • The base is 22.
  • The exponent is 55.
  • The result is 3232.

Step 2: Use the conversion pattern.

Since

ab=cloga(c)=b,a^b=c \quad\Longleftrightarrow\quad \log_a(c)=b,

substitute a=2a=2, b=5b=5, and c=32c=32:

log2(32)=5\boxed{\log_2(32)=5}

This means “the exponent to which 22 must be raised to get 3232 is 55.”

The conversion also works in reverse. Starting with

log2(32)=5,\log_2(32)=5,

rewrite it as

25=32.\boxed{2^5=32}.

Always check that the base is positive and not 11, and that the logarithm’s argument is positive.

Learn by doing: Convert between exponential and logarithmic form

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Logarithms - Convert Exponent to Logarithm - Fraction Value


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