Skill: Determine amplitude, period, phase shift, and vertical displacement

Explanation and Free Practice Resources

For sinusoidal functions in the form y=Asin⁡(B(x−C))+Dy=A\sin(B(x-C))+D or y=Acos⁡(B(x−C))+Dy=A\cos(B(x-C))+D, the learner interprets amplitude as ∣A∣|A|, period as 2π/∣B∣2\pi/|B| (or 360∘/∣B∣360^\circ/|B|), phase shift as CC, and vertical displacement as DD, identifying the midline y=Dy=D and the effect of a negative AA as reflection. The understanding connects algebraic parameters with graph features and is limited to standard sinusoidal transformations, not advanced Fourier analysis or generalized periodic-function theory.

Detailed Explanation: Determine amplitude, period, phase shift, and vertical displacement

To identify the features of a sinusoidal function, compare it with one of these forms:

y=Asin⁡(B(x−C))+Dy=A\sin(B(x-C))+D

or

y=Acos⁡(B(x−C))+D.y=A\cos(B(x-C))+D.

The parameters have these meanings:

  • Amplitude: ∣A∣\lvert A\rvert
  • Period: 2π∣B∣\dfrac{2\pi}{\lvert B\rvert} radians, or 360∘∣B∣\dfrac{360^\circ}{\lvert B\rvert} degrees
  • Phase shift: CC
    • C>0C>0 means a shift right.
    • C<0C<0 means a shift left.
  • Vertical displacement: DD
  • Midline: y=Dy=D
  • If A<0A<0, the graph is reflected across its midline.

Example

Determine the amplitude, period, phase shift, and vertical displacement of

y=−3cos⁡(2(x−π4))+2.y=-3\cos\left(2\left(x-\frac{\pi}{4}\right)\right)+2.

Step 1: Identify the parameters

Compare the function with

y=Acos⁡(B(x−C))+D.y=A\cos(B(x-C))+D.

We can see that

A=−3,B=2,C=π4,D=2.A=-3,\qquad B=2,\qquad C=\frac{\pi}{4},\qquad D=2.

Step 2: Find the amplitude

The amplitude is the absolute value of AA:

Amplitude=∣−3∣=3.\text{Amplitude}=\lvert -3\rvert=3.

The negative sign does not make the amplitude negative. Instead, it reflects the cosine graph across its midline.

Step 3: Find the period

Using radians,

Period=2π∣B∣=2π2=π.\text{Period}=\frac{2\pi}{\lvert B\rvert} =\frac{2\pi}{2} =\pi.

So the graph completes one full cycle every π\pi units.

Step 4: Find the phase shift

The expression is

x−π4,x-\frac{\pi}{4},

so

Phase shift=π4.\text{Phase shift}=\frac{\pi}{4}.

The graph shifts π4\frac{\pi}{4} units to the right.

Step 5: Find the vertical displacement and midline

The value of DD is 22, so

Vertical displacement=2.\text{Vertical displacement}=2.

The midline is therefore

y=2.y=2.

Thus, the function has:

  • Amplitude: 33
  • Period: π\pi
  • Phase shift: π4\frac{\pi}{4} units right
  • Vertical displacement: 22 units up
  • Midline: y=2y=2
  • Reflection: Yes, because A=−3A=-3

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Sinusoidal Function Parameters (4 Params) - Function to Parameters


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