Skill: Determine phase shift of a sinusoidal function

Explanation and Free Practice Resources

Phase shift is the horizontal translation of a sinusoidal graph, identified by rewriting an equation in the form y=asin⁡[b(x−h)]+dy=a\sin[b(x-h)]+d or y=acos⁡[b(x−h)]+dy=a\cos[b(x-h)]+d, where hh is the shift and the period is 2π/∣b∣2\pi/|b|. In forms such as y=asin⁡(bx+c)+dy=a\sin(bx+c)+d, the phase shift is −c/b-c/b, so the sign is opposite the apparent constant inside the function; amplitude and vertical shift do not alter it.

Detailed Explanation: Determine phase shift of a sinusoidal function

The phase shift tells you how far a sinusoidal graph moves horizontally.

Rewrite the equation so the angle has the form

b(x−h).b(x-h).

Then hh is the phase shift:

  • If h>0h>0, the graph shifts right.
  • If h<0h<0, the graph shifts left.

For an equation in the form

y=asin⁡(bx+c)+d,y=a\sin(bx+c)+d,

the phase shift is

−cb.-\frac{c}{b}.

The negative sign is important.

Worked example

Determine the phase shift of

y=3sin⁡(2x+π3)−1.y=3\sin\left(2x+\frac{\pi}{3}\right)-1.

Step 1: Identify the values inside the sine function.

The angle is

2x+π3.2x+\frac{\pi}{3}.

Here, b=2b=2 and c=π3c=\frac{\pi}{3}.

Step 2: Use the phase-shift formula.

Phase shift=−cb=−π32=−π6.\text{Phase shift}=-\frac{c}{b} =-\frac{\frac{\pi}{3}}{2} =-\frac{\pi}{6}.

Step 3: Interpret the answer.

A phase shift of

−π6-\frac{\pi}{6}

means the graph shifts left π6\frac{\pi}{6}.

You can also see this by factoring the angle:

2x+π3=2(x+π6)=2(x−(−π6)).2x+\frac{\pi}{3} =2\left(x+\frac{\pi}{6}\right) =2\left(x-\left(-\frac{\pi}{6}\right)\right).

This matches the form b(x−h)b(x-h), so

h=−π6.h=-\frac{\pi}{6}.

The numbers 33 and −1-1 change the amplitude and vertical position, but they do not affect the phase shift.

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