Divide a 2-digit number by a 1-digit number

This understanding involves partitioning a two-digit dividend into equal groups of a one-digit divisor, using place value to decompose tens and ones and determine a whole-number quotient, with or without a remainder. The relationship is represented by equations such as $D=dq+r$ , where the remainder is less than the divisor, and connected to multiplication as its inverse; decimal quotients, fractional remainders, and larger or multi-digit divisors are outside this scope.

Detailed Explanation: Divide a 2-digit number by a 1-digit number

To divide a 2-digit number by a 1-digit number, split the dividend into tens and ones. Divide each part, then combine the groups.

Example: $67 \div 3$

Split $67$ into tens and ones:

67=60+7

Divide the tens:

60\div 3=20

So, there are $20$ groups from the tens.

Divide the ones:

7\div 3=2\text{ remainder }1

There are $2$ more groups, with $1$ left over.

Combine the groups:

20+2=22

Therefore,

67\div 3=22\text{ remainder }1

Check the answer using multiplication:

3\times 22+1=67

The remainder, $1$ , is less than the divisor, $3$ , so the answer is correct.

Learn by doing: Divide a 2-digit number by a 1-digit number

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Long Division - No Remainder 2 x 1

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