Skill: Estimate square roots

Explanation and Free Practice Resources

Square-root estimation involves locating the principal nonnegative value whose square equals or approximates a given nonnegative number, using nearby perfect squares as benchmarks. A learner can bound roots of integers and familiar decimals between consecutive whole numbers and refine those bounds to tenths or hundredths by comparing squared estimates, while understanding that non-perfect-square roots are generally irrational and that the square-root operation reverses squaring only for nonnegative values.

Detailed Explanation: Estimate square roots

To estimate a square root, find nearby perfect squares and use them as benchmarks. Remember that n\sqrt{n} means the principal, nonnegative number whose square is nn.

Example: Estimate 50\sqrt{50} to the nearest hundredth.

  1. Find the perfect squares around 5050:

72=4982=647^2=49 \qquad 8^2=64

Since 5050 is between 4949 and 6464,

7<50<8.7<\sqrt{50}<8.
  1. Refine the estimate to tenths. Try 7.17.1:

7.12=50.417.1^2=50.41

Because 5050 is between 7.02=497.0^2=49 and 7.12=50.417.1^2=50.41,

7.0<50<7.1.7.0<\sqrt{50}<7.1.
  1. Refine to hundredths. Try 7.077.07 and 7.087.08:

7.072=49.98497.07^2=49.9849 7.082=50.12647.08^2=50.1264

Therefore,

49.9849<50<50.1264,49.9849<50<50.1264,

so

7.07<50<7.08.7.07<\sqrt{50}<7.08.

Thus, to the nearest hundredth,

50≈7.07.\boxed{\sqrt{50}\approx 7.07}.

The estimate is not exactly equal to 50\sqrt{50} because 5050 is not a perfect square.

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