Skill: Factor differences of squares

Explanation and Free Practice Resources

A difference of two perfect squares, a2−b2a^2-b^2, factors as the product of the conjugate binomials (a−b)(a+b)(a-b)(a+b). This understanding includes recognizing squared monomials and numerical terms in polynomial expressions, applying the pattern with integer or rational coefficients, and checking the result by multiplication; it distinguishes differences of squares from sums of squares, without extending to complex-number factorization or more advanced generalizations.

Detailed Explanation: Factor differences of squares

A difference of squares has the form

a2−b2a^2-b^2

It factors using the pattern

a2−b2=(a−b)(a+b).a^2-b^2=(a-b)(a+b).

The expression must have:

  • subtraction between two terms, and
  • each term must be a perfect square.

Example: Factor (25x2−16)(25x^2-16)

Step 1: Recognize the two squares.

Both terms are perfect squares:

25x2=(5x)225x^2=(5x)^2

and

16=42.16=4^2.

So rewrite the expression as

25x2−16=(5x)2−42.25x^2-16=(5x)^2-4^2.

Step 2: Apply the difference-of-squares pattern.

Here, (a=5x)(a=5x) and (b=4)(b=4). Therefore,

(5x)2−42=(5x−4)(5x+4).(5x)^2-4^2=(5x-4)(5x+4).

So the factored form is

(5x−4)(5x+4).\boxed{(5x-4)(5x+4)}.

Step 3: Check by multiplying.

Use the distributive property:

(5x−4)(5x+4)=25x2+20x−20x−16=25x2−16.(5x-4)(5x+4) =25x^2+20x-20x-16 =25x^2-16.

The middle terms cancel, confirming the answer.

Remember: this pattern applies to a difference, or subtraction, of squares. An expression such as (x2+9)(x^2+9) is a sum of squares and does not factor using this pattern over the real numbers.

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Factor Polynomials (Order 3) - By Grouping, Order 2 Factors to Order 1 Factors, Coefficient 1


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