Skill: Factor higher-degree polynomials

Explanation and Free Practice Resources

Factoring higher-degree polynomials involves using structure—common factors, grouping, identities, substitution, the Factor Theorem, the Rational Root Theorem, and polynomial division—to express a polynomial as a product of lower-degree factors. The factorization connects factors with zeros, multiplicities, and graph behavior, while preserving equivalence through expansion; work is limited to polynomial degrees and integer or rational coefficients typically encountered, without requiring general formulas or factorization over abstract number systems.

Detailed Explanation: Factor higher-degree polynomials

When a polynomial has degree 33 or greater, look for rational zeros first. If rr is a zero of P(x)P(x), then (x−r)(x-r) is a factor.

Consider

P(x)=x4−2x3−7x2+8x+12.P(x)=x^4-2x^3-7x^2+8x+12.

1. List possible rational zeros

Because the leading coefficient is 11, the Rational Root Theorem says that any rational zero must be a factor of the constant term 1212:

±1, ±2, ±3, ±4, ±6, ±12.\pm1,\ \pm2,\ \pm3,\ \pm4,\ \pm6,\ \pm12.

Test a simple candidate:

P(2)=16−16−28+16+12=0.P(2)=16-16-28+16+12=0.

Therefore, x=2x=2 is a zero, so (x−2)(x-2) is a factor.

2. Divide by the factor

Use synthetic division:

Thus,

P(x)=(x−2)(x3−7x−6).P(x)=(x-2)(x^3-7x-6).

3. Factor the remaining polynomial

Test another possible rational zero in the cubic:

33−7(3)−6=27−21−6=0.3^3-7(3)-6=27-21-6=0.

So x=3x=3 is a zero, and (x−3)(x-3) is a factor. Dividing gives

x3−7x−6=(x−3)(x2+3x+2).x^3-7x-6=(x-3)(x^2+3x+2).

Now factor the quadratic:

x2+3x+2=(x+1)(x+2).x^2+3x+2=(x+1)(x+2).

Therefore, the complete factorization is

x4−2x3−7x2+8x+12=(x−2)(x−3)(x+1)(x+2).\boxed{x^4-2x^3-7x^2+8x+12=(x-2)(x-3)(x+1)(x+2)}.

Always check by multiplying the factors back together. The product expands to the original polynomial, confirming that the factorization is correct.

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Factor Polynomials (Order 3) - By Grouping to Order 1 Factors, Coefficient 1


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