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Identify horizontal stretches and compressions

A horizontal stretch or compression changes the input scale while preserving output values: for g(x)=f(bx)g(x)=f(bx) with b>0b>0, each point (x,y)(x,y) on ff maps to (x/b,y)(x/b,y); b>1b>1 produces a horizontal compression by factor 1/b1/b, while 0<b<10<b<1 produces a stretch by factor 1/b1/b. This relationship is interpreted across equations, graphs, and point mappings, emphasizing that an input multiplier acts reciprocally and is distinct from a vertical scale factor; negative factors and more generalized parameter analysis are outside this scope.

Detailed Explanation: Identify horizontal stretches and compressions

A horizontal transformation changes the input values of a function, so the yy-values stay the same.

For a function

g(x)=f(bx),b>0,g(x)=f(bx), \qquad b>0,

each point (x,y)(x,y) on the graph of ff moves to

(xb,y).\left(\frac{x}{b},y\right).

The input multiplier bb works reciprocally:

  • If b>1b>1, the graph is horizontally compressed by a factor of 1b\frac{1}{b}.
  • If 0<b<10<b<1, the graph is horizontally stretched by a factor of 1b\frac{1}{b}.

Example

Suppose the graph of ff contains the point (6,4)(6,4). Describe the transformation and find the corresponding point on

g(x)=f(2x).g(x)=f(2x).

Step 1: Identify the input multiplier.

The expression inside ff is 2x2x, so

b=2.b=2.

Step 2: Determine the type of horizontal change.

Because b=2>1b=2>1, the graph is horizontally compressed by a factor of

12.\frac{1}{2}.

Step 3: Apply the point rule.

Divide the xx-coordinate by 22, but leave the yy-coordinate unchanged:

(6,4)⟶(62,4)=(3,4).(6,4)\longrightarrow \left(\frac{6}{2},4\right)=(3,4).

So, the point (6,4)(6,4) on ff becomes (3,4)(3,4) on gg. The graph moves closer to the yy-axis horizontally, while its output value, 44, remains the same.

Learn by doing: Identify horizontal stretches and compressions

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Function Transformations - Mapping Notation - Single Transformation to Action


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