Skill: Identify reflections across the y-axis

Explanation and Free Practice Resources

A reflection across the yy-axis maps each point (x,y)(x,y) to (−x,y)(-x,y): horizontal position reverses while vertical position remains unchanged, so the reflected graph of y=f(x)y=f(x) is y=f(−x)y=f(-x), with the domain reflected and the range preserved. This distinguishes f(−x)f(-x), a yy-axis reflection, from −f(x)-f(x), an xx-axis reflection, and supports interpreting symmetry and combining function transformations.

Detailed Explanation: Identify reflections across the y-axis

A reflection across the yy-axis changes the sign of every xx-coordinate but keeps the yy-coordinate the same:

(x,y)⟶(−x,y).(x,y)\longrightarrow(-x,y).

For a function, this means replace xx with (−x)(-x):

y=f(x)⟶y=f(−x).y=f(x)\quad\longrightarrow\quad y=f(-x).

Example

Reflect the graph of

f(x)=x−2+1f(x)=\sqrt{x-2}+1

across the yy-axis.

Step 1: Replace xx with (−x)(-x).

f(−x)=(−x)−2+1f(-x)=\sqrt{(-x)-2}+1

So the reflected function is

y=−x−2+1.\boxed{y=\sqrt{-x-2}+1}.

Step 2: Check the point movement.

The original function has an endpoint at (2,1)(2,1). Reflecting it across the yy-axis changes only the xx-coordinate:

(2,1)⟶(−2,1).(2,1)\longrightarrow(-2,1).

The reflected graph therefore begins at (−2,1)(-2,1) and extends to the left.

Step 3: Identify the domain and range.

For the reflected function, the expression inside the square root must be nonnegative:

−x−2≥0,-x-2\ge 0,

so

x≤−2.x\le -2.

Thus, the domain is (−∞,−2](-\infty,-2]. The yy-values have not changed, so the range remains [1,∞)[1,\infty).

Remember:

  • f(−x)f(-x) reflects a graph across the yy-axis.
  • −f(x)-f(x) reflects a graph across the xx-axis.

For this example, the answer is

y=−x−2+1.\boxed{y=\sqrt{-x-2}+1}.

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