Skill: Select an appropriate trigonometric ratio

Explanation and Free Practice Resources

The learner identifies the given acute angle and matches the available side relationships to sine (opposite/hypotenuse), cosine (adjacent/hypotenuse), or tangent (opposite/adjacent), recognizing that “opposite” and “adjacent” depend on the chosen reference angle. This supports setting up right-triangle proportions to determine unknown sides or angles; inverse trigonometric functions, non-right triangles, and generalized trigonometric identities are beyond this scope.

Detailed Explanation: Select an appropriate trigonometric ratio

To choose a trigonometric ratio, first focus on the given acute angle. Then name the sides from the angle’s point of view:

  • Opposite: the side directly across from the angle
  • Adjacent: the side next to the angle that is not the hypotenuse
  • Hypotenuse: the longest side, always opposite the right angle

Use the ratio that includes the sides you know and the side you want:

sin⁡(θ)=oppositehypotenuse\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}} cos⁡(θ)=adjacenthypotenuse\cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}} tan⁡(θ)=oppositeadjacent\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}

Example

A right triangle has an angle of 40∘40^\circ. The side next to the 40∘40^\circ angle has length xx, and the hypotenuse has length 1515. Find xx.

Step 1: Identify the sides relative to the 40∘40^\circ angle.

  • Adjacent side: xx
  • Hypotenuse: 1515

Step 2: Choose the ratio.

The available sides are adjacent and hypotenuse, so use cosine:

cos⁡(θ)=adjacenthypotenuse\cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}

Step 3: Substitute the known values.

cos⁡(40∘)=x15\cos(40^\circ)=\frac{x}{15}

Step 4: Solve for xx.

Multiply both sides by 1515:

x=15cos⁡(40∘)x=15\cos(40^\circ)

Using a calculator:

x≈11.5x\approx 11.5

So, the missing side is approximately

11.5\boxed{11.5}

Always identify the sides in relation to the chosen angle before selecting sine, cosine, or tangent.

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