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Solve simple logarithmic equations

Solving simple logarithmic equations involves interpreting logarithms as exponents and using the inverse relationship between logarithmic and exponential forms to solve equations such as logb(x)=c\log_b(x)=c, logb(f(x))=c\log_b(f(x))=c, or equal logarithms with the same valid base. The reasoning includes enforcing positive arguments and rejecting solutions outside the domain; this scope excludes complex solutions, nonlinear logarithmic systems, and advanced manipulation of lengthy logarithmic expressions.

Detailed Explanation: Solve simple logarithmic equations

A logarithmic equation can often be solved by rewriting it in exponential form.

Remember:

logb(x)=cbc=x\log_b(x)=c \quad \Longleftrightarrow \quad b^c=x

The base must satisfy b>0b>0 and b1b\ne 1, and the logarithm’s argument must be positive.

Example

Solve:

log3(2x1)=2\log_3(2x-1)=2

Step 1: Rewrite in exponential form.

The base is 33, the exponent is 22, and the argument is 2x12x-1:

32=2x13^2=2x-1

Step 2: Simplify and solve for xx.

9=2x19=2x-1

Add 11 to both sides:

10=2x10=2x

Divide by 22:

x=5x=5

Step 3: Check the domain.

The argument of a logarithm must be positive:

2x1>02x-1>0

Substitute x=5x=5:

2(5)1=9>02(5)-1=9>0

So the solution is valid.

x=5\boxed{x=5}

Learn by doing: Solve simple logarithmic equations

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Logarithms - Solve Log Equation (From Decimals)


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