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Solve systems of equations by substitution

Substitution solves a system of two linear equations by recognizing that equivalent expressions for the same variable can be set equal: isolate a variable in one equation, replace it in the other, and determine the remaining variable before finding the ordered-pair solution. The solution satisfies both relationships and represents the intersection of their lines; checking it in both original equations helps distinguish one solution, no solution, and infinitely many solutions. The scope is limited to familiar two-variable linear systems, not nonlinear systems or matrix-based methods.

Detailed Explanation: Solve systems of equations by substitution

Substitution works by replacing one variable with an equivalent expression.

Consider the system:

2x+y=11x−y=1\begin{aligned} 2x+y&=11\\ x-y&=1 \end{aligned}

1. Isolate one variable

Use the first equation and solve for yy:

2x+y=112x+y=11

Subtract 2x2x from both sides:

y=11−2xy=11-2x

Now we know that yy is equivalent to 11−2x11-2x.

2. Substitute into the other equation

The second equation is:

x−y=1x-y=1

Replace yy with 11−2x11-2x:

x−(11−2x)=1x-(11-2x)=1

3. Solve for the remaining variable

Distribute the negative sign:

x−11+2x=1x-11+2x=1

Combine like terms:

3x−11=13x-11=1

Add 1111 to both sides:

3x=123x=12

Divide by 33:

x=4x=4

4. Find the other variable

Substitute x=4x=4 into y=11−2xy=11-2x:

y=11−2(4)y=11-2(4) y=11−8=3y=11-8=3

So the solution is:

(4,3)\boxed{(4,3)}

5. Check the solution

Substitute x=4x=4 and y=3y=3 into both original equations:

2(4)+3=112(4)+3=11 4−3=14-3=1

Both equations are true, so (4,3)(4,3) is the solution. It represents the point where the two lines intersect.

Learn by doing: Solve systems of equations by substitution

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Linear Equations - Find Intersection (Decimal) - Two Linear Equations


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