Skill: Use divisibility rules for 3 and 9

Explanation and Free Practice Resources

In base-ten whole numbers, divisibility by 3 or 9 can be determined by adding the digits: a number is divisible by 3 exactly when its digit sum is divisible by 3, and divisible by 9 exactly when its digit sum is divisible by 9. This supports identifying factors and multiples and distinguishing that every multiple of 9 is a multiple of 3, but not every multiple of 3 is a multiple of 9; formal modular arithmetic and generalized proofs are beyond this scope.

Detailed Explanation: Use divisibility rules for 3 and 9

To test whether a whole number is divisible by 33 or 99, add its digits.

  • If the digit sum is divisible by 33, the number is divisible by 33.
  • If the digit sum is divisible by 99, the number is divisible by 99.

Example: Is (2,145)(2{,}145) divisible by 33 or 99?

Step 1: Add the digits.

2+1+4+5=122+1+4+5=12

Step 2: Check (12)(12).

  • (12)(12) is divisible by 33, because (12=3×4)(12=3\times4).
  • (12)(12) is not divisible by 99.

Step 3: State the answer.

Therefore, (2,145)(2{,}145) is divisible by 33, but it is not divisible by 99.

Remember: Every number divisible by 99 is also divisible by 33, but a number divisible by 33 is not always divisible by 99.

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Divisibility Rules (Easy) - Dividend and Condition to Yes/No


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