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Use the remainder theorem

For a polynomial f(x)f(x), division by the linear polynomial xax-a leaves the constant remainder f(a)f(a); thus evaluating a polynomial at aa is equivalent to finding its remainder upon division by xax-a. This understanding supports efficient evaluation, interpretation of polynomial division, and the factor theorem: xax-a is a factor exactly when f(a)=0f(a)=0. The scope is limited to linear divisors and standard real- or integer-coefficient polynomial examples, not higher-degree divisors or abstract coefficient systems.

Detailed Explanation: Use the remainder theorem

The remainder theorem says:

When a polynomial f(x)f(x) is divided by xax-a, the remainder is f(a)f(a).

So, instead of performing long division, substitute aa into the polynomial.

Example

Find the remainder when

f(x)=2x33x2+4x5f(x)=2x^3-3x^2+4x-5

is divided by x2x-2.

Step 1: Identify aa

The divisor is x2x-2, which has the form xax-a. Therefore,

a=2a=2

Step 2: Evaluate f(2)f(2)

Substitute 22 for xx:

f(2)=2(2)33(2)2+4(2)5f(2)=2(2)^3-3(2)^2+4(2)-5

Simplify:

f(2)=2(8)3(4)+85f(2)=2(8)-3(4)+8-5 f(2)=1612+85=7f(2)=16-12+8-5=7

Step 3: State the remainder

The remainder is

7\boxed{7}

Therefore, dividing 2x33x2+4x52x^3-3x^2+4x-5 by x2x-2 leaves a remainder of 77.

If f(a)=0f(a)=0, then the remainder is zero, which means xax-a is a factor of f(x)f(x).

Learn by doing: Use the remainder theorem

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Factor Theorem - Find the Remainder Given a Binomial Divisor


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