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Calculate the surface area of pyramids

Surface area of a pyramid is the sum of the base area and the areas of its triangular lateral faces; for a regular pyramid, this can be expressed as SA=B+12PlSA=B+\tfrac12Pl, where BB is base area, PP base perimeter, and ll slant height. The distinction between slant height and perpendicular height is essential, with the latter used to find ll when needed through right-triangle relationships; treatment is limited to common right or regular pyramids, not generalized oblique or advanced cases.

Detailed Explanation: Calculate the surface area of pyramids

The surface area of a regular pyramid is the area of its base plus the areas of all its triangular faces.

Use the formula

SA=B+12PlSA=B+\frac12Pl

where:

  • BB is the area of the base,
  • PP is the perimeter of the base,
  • ll is the slant height.

The slant height goes from the midpoint of a base edge to the apex along a triangular face. It is different from the perpendicular height, which goes straight from the apex to the center of the base.

Example

Find the surface area of a square pyramid with:

  • base side length 66 cm,
  • perpendicular height 44 cm.

Step 1: Find the base area

The base is a square:

B=62=36 cm2B=6^2=36\text{ cm}^2

Step 2: Find the base perimeter

P=4(6)=24 cmP=4(6)=24\text{ cm}

Step 3: Find the slant height

The perpendicular height, half of the base side, and slant height form a right triangle.

Half of the base side is

62=3 cm\frac{6}{2}=3\text{ cm}

Using the Pythagorean theorem:

l2=42+32l^2=4^2+3^2 l2=16+9=25l^2=16+9=25 l=5 cml=5\text{ cm}

Step 4: Substitute into the surface area formula

SA=B+12PlSA=B+\frac12Pl SA=36+12(24)(5)SA=36+\frac12(24)(5) SA=36+60SA=36+60 SA=96 cm2\boxed{SA=96\text{ cm}^2}

The surface area of the pyramid is 96 cm2\boxed{96\text{ cm}^2}.

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Surface Area - All - Words to Decimal


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