Skill: Compare financing options

Explanation and Free Practice Resources

Comparing financing options involves interpreting principal, down payment, interest rate, compounding or payment frequency, term, periodic payment, fees, and total amount repaid for standard fixed-rate loans or installment purchases. The learner reasons that a smaller periodic payment can produce a greater total cost when the term is longer and distinguishes an advertised interest rate from the overall financing cost, including fees, using equations, tables, and amortization schedules. Variable-rate loans, refinancing, tax effects, inflation adjustments, and advanced present-value models are outside this scope.

Detailed Explanation: Compare financing options

To compare financing options, do not look only at the periodic payment or advertised interest rate. Compare:

  • the amount borrowed, after the down payment;
  • the interest rate and payment frequency;
  • the number of payments;
  • fees;
  • the total amount paid.

A longer loan term often has a smaller payment but a greater total cost.

Example

A laptop costs 20{,}000.Youmakea. You make a $2{,}000$ down payment, so the amount financed is

P=20,000−2,000=$18,000.P=20{,}000-2{,}000=\$18{,}000.

You are comparing two fixed-rate loans. Both use monthly payments.

OptionAnnual interest rateTermFee
A6%6\%3 years200$
B5.5%5.5\%5 years0$

Step 1: Find the monthly rate and number of payments

For a monthly loan,

i=annual rate12andn=(years)(12).i=\frac{\text{annual rate}}{12} \qquad\text{and}\qquad n=(\text{years})(12).

For Option A,

i=0.0612=0.005,n=3(12)=36.i=\frac{0.06}{12}=0.005, \qquad n=3(12)=36.

For Option B,

i=0.05512=0.004583,n=5(12)=60.i=\frac{0.055}{12}=0.004583, \qquad n=5(12)=60.

Step 2: Calculate each monthly payment

For a standard fixed-rate loan, use

M=P(i1−(1+i)−n),M=P\left(\frac{i}{1-(1+i)^{-n}}\right),

where MM is the periodic payment.

For Option A,

MA=18,000(0.0051−(1.005)−36)≈$547.59.M_A =18{,}000\left(\frac{0.005}{1-(1.005)^{-36}}\right) \approx \$547.59.

For Option B,

MB=18,000(0.0045831−(1.004583)−60)≈$343.82.M_B =18{,}000\left(\frac{0.004583}{1-(1.004583)^{-60}}\right) \approx \$343.82.

Option B has the smaller monthly payment.

Step 3: Find the total of the loan payments

Multiply the payment by the number of payments.

For Option A,

36($547.59)≈$19,713.24.36(\$547.59)\approx \$19{,}713.24.

Adding the 200$ fee,

loan cost for A=$19,713.24+$200=$19,913.24.\text{loan cost for A} =\$19{,}713.24+\$200 =\$19{,}913.24.

For Option B,

60($343.82)≈$20,629.20.60(\$343.82)\approx \$20{,}629.20.

There is no fee, so

loan cost for B=$20,629.20.\text{loan cost for B}=\$20{,}629.20.

Step 4: Include the down payment

The total amount paid for the laptop is the down payment plus the loan cost.

OptionDown paymentPayments and feesTotal paid
A2{,}000$19{,}913.24$21{,}913.24$
B2{,}000$20{,}629.20$22{,}629.20$

Option A is cheaper overall by approximately

$22,629.20−$21,913.24=$715.96.\$22{,}629.20-\$21{,}913.24=\$715.96.

Although Option B advertises a lower interest rate and has a much smaller monthly payment, its five-year term means interest is charged for more months. Therefore, Option A is the better financing choice if the goal is to pay the least overall.

Learn by doing: Compare financing options

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Financial Literacy - Interest and Fees - Compound Discrete - Comparison With Fees to Better Option


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