Skill: Divide multi-digit numbers by 2-digit divisors

Explanation and Free Practice Resources

Whole-number division with typically up to four-digit dividends and two-digit divisors is understood through place value: the dividend is decomposed into groups, and each quotient digit represents how many groups of the divisor fit at that place. The quotient and remainder satisfy dividend=divisor×quotient+remainder\text{dividend}=\text{divisor}\times\text{quotient}+\text{remainder}, with the remainder less than the divisor; estimation checks the quotient’s size and the remainder is interpreted as a quantity, not appended as another digit. The scope is whole-number quotients and remainders, excluding decimal division and more general rational divisors.

Detailed Explanation: Divide multi-digit numbers by 2-digit divisors

To divide by a two-digit divisor, use place value and divide one part of the dividend at a time.

Example: Find (1,487÷27)(1{,}487 \div 27).

First, estimate:

1,500÷30≈501{,}500 \div 30 \approx 50

So the answer should be close to (50)(50).

Step 1: Divide the first group

(27)(27) does not fit into 11 or (14)(14), so use (148)(148).

Ask: How many groups of (27)(27) fit into (148)(148)?

27×5=13527 \times 5=135

So write 55 in the tens place of the quotient.

Subtract:

148−135=13148-135=13

Step 2: Bring down the next digit

Bring down the 77 to make (137)(137).

Ask: How many groups of (27)(27) fit into (137)(137)?

27×5=13527 \times 5=135

Write another 55 in the ones place of the quotient.

Subtract:

137−135=2137-135=2

There are no more digits to bring down, so 22 is the remainder.

1,487÷27=55 R 2\boxed{1{,}487\div27=55\text{ R }2}

Check the answer:

27×55+2=1,485+2=1,48727\times55+2=1{,}485+2=1{,}487

The remainder 22 is less than the divisor (27)(27), so the answer is correct.

Learn by doing: Divide multi-digit numbers by 2-digit divisors

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Long Division - No Remainder 4 x 2


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