Skill: Apply properties of matrix transposes

Explanation and Free Practice Resources

Transposition interchanges a matrix’s rows and columns, so an m×nm\times n matrix becomes an n×mn\times m matrix. For real matrices, transposing twice returns the original matrix; transposition distributes over addition and scalar multiplication, while reversing the order of factors in a product: (AB)T=BTAT(AB)^T=B^TA^T, when the products are defined. This treatment does not extend to complex conjugate transposes or more abstract generalizations.

Detailed Explanation: Apply properties of matrix transposes

Transposing a matrix means switching its rows and columns. An m×nm\times n matrix becomes an n×mn\times m matrix. For real matrices, useful rules are

(A+B)T=AT+BT,(kA)T=kAT,(AB)T=BTAT,(AT)T=A.(A+B)^T=A^T+B^T,\qquad (kA)^T=kA^T,\qquad (AB)^T=B^TA^T,\qquad (A^T)^T=A.

The key detail in a product is that the order reverses.

Example: Let

A=(120−1),B=(3120),C=(1021).A=\begin{pmatrix}1&2\\0&-1\end{pmatrix},\quad B=\begin{pmatrix}3&1\\2&0\end{pmatrix},\quad C=\begin{pmatrix}1&0\\2&1\end{pmatrix}.

Find ((2A+B)C)T\bigl((2A+B)C\bigr)^T.

First, apply the product rule, reversing the order of the factors:

((2A+B)C)T=CT(2A+B)T.\bigl((2A+B)C\bigr)^T=C^T(2A+B)^T.

Next, use the scalar and addition rules:

CT(2A+B)T=CT(2AT+BT).C^T(2A+B)^T=C^T(2A^T+B^T).

To check the result, calculate inside the original expression:

2A+B=(552−2),(2A+B)C=(155−2−2).2A+B=\begin{pmatrix}5&5\\2&-2\end{pmatrix}, \qquad (2A+B)C=\begin{pmatrix}15&5\\-2&-2\end{pmatrix}.

Therefore,

((2A+B)C)T=(15−25−2).\bigl((2A+B)C\bigr)^T =\begin{pmatrix}15&-2\\5&-2\end{pmatrix}.

When transposing a product, transpose each factor and write the factors in reverse order.

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Matrices - Transpose (3x3) - Matrix to Answer


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