Skill: Calculate the inverse of a 2 by 2 matrix

Explanation and Free Practice Resources

For a 2×2 matrix with real entries, the inverse is the matrix that undoes its action: multiplying the matrix by its inverse in either order gives the identity matrix. Its entries are obtained by swapping the diagonal entries, negating the off-diagonal entries, and dividing by the determinant; an inverse exists only when the determinant is nonzero, so a matrix with determinant zero cannot be inverted. This treatment does not extend to larger matrices or more general number systems.

Detailed Explanation: Calculate the inverse of a 2 by 2 matrix

For a 2×22\times2 matrix

A=(abcd),A=\begin{pmatrix}a&b\\c&d\end{pmatrix},

first calculate its determinant, ad−bcad-bc. If the determinant is zero, the matrix has no inverse. Otherwise, swap the diagonal entries, change the signs of the off-diagonal entries, and divide every entry by the determinant:

A−1=1ad−bc(d−b−ca).A^{-1}=\frac{1}{ad-bc}\begin{pmatrix}d&-b\\-c&a\end{pmatrix}.

Example: Find the inverse of

A=(2314).A=\begin{pmatrix}2&3\\1&4\end{pmatrix}.
  1. Calculate the determinant:
2(4)−3(1)=5.2(4)-3(1)=5.

Since 5≠05\ne0, the inverse exists.

  1. Swap the diagonal entries, 22 and 44, and change the signs of 33 and 11:
(4−3−12).\begin{pmatrix}4&-3\\-1&2\end{pmatrix}.
  1. Divide by the determinant:
A−1=15(4−3−12)=(45−35−1525). A^{-1}=\frac15\begin{pmatrix}4&-3\\-1&2\end{pmatrix} =\begin{pmatrix}\frac45&-\frac35\\-\frac15&\frac25\end{pmatrix}.

You can check the result by multiplying AA by A−1A^{-1}; the product is the identity matrix (1001)\begin{pmatrix}1&0\\0&1\end{pmatrix}.

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Matrices - Matrix to Inverse (2x2, with Formula)


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