Skill: Expand a determinant along a specified row

Explanation and Free Practice Resources

For a 3×3 determinant, expansion along a chosen row expresses the determinant as the sum of each row entry multiplied by the determinant of its corresponding 2×2 minor, with alternating cofactor signs +,−,++,-,+. Deleting the chosen row and each entry’s column forms the minors; the sign pattern is essential, and expanding along any row gives the same determinant. General determinant expansions for larger matrices are not included.

Detailed Explanation: Expand a determinant along a specified row

To expand a 3×33\times3 determinant along a row, use each entry in that row with its matching 2×22\times2 minor. For the first row, the cofactor signs are +,−,++,-,+. To form a minor, delete the chosen entry’s row and column. Then evaluate each 2×22\times2 determinant using ad−bcad-bc.

Expand this determinant along the first row:

∣2130−14521∣\begin{vmatrix} 2 & 1 & 3\\ 0 & -1 & 4\\ 5 & 2 & 1 \end{vmatrix}

The first-row entries are 22, 11, and 33.

  • For 22, delete the first row and first column:
∣−1421∣=(−1)(1)−(4)(2)=−9 \begin{vmatrix}-1&4\\2&1\end{vmatrix} =(-1)(1)-(4)(2)=-9
  • For 11, delete the first row and second column:
∣0451∣=(0)(1)−(4)(5)=−20 \begin{vmatrix}0&4\\5&1\end{vmatrix} =(0)(1)-(4)(5)=-20
  • For 33, delete the first row and third column:
∣0−152∣=(0)(2)−(−1)(5)=5 \begin{vmatrix}0&-1\\5&2\end{vmatrix} =(0)(2)-(-1)(5)=5

Apply the +,−,++,-,+ signs and multiply by the corresponding first-row entries:

2(−9)−1(−20)+3(5)=−18+20+15=172(-9)-1(-20)+3(5)=-18+20+15=\boxed{17}

The determinant is 1717.

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Matrices - Determinant (3x3) Cofactor Expansion - Matrix to Answer


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