Skill: Simplify expressions involving matrix addition, subtraction, and scalar multiplication

Explanation and Free Practice Resources

For matrices with real-number entries, addition and subtraction combine corresponding entries and require matrices of the same dimensions; scalar multiplication multiplies every entry by the scalar. Simplifying expressions relies on distributing scalars and combining coefficients of identical matrices while preserving subtraction order and parentheses; matrix multiplication, inverses, and more abstract matrix structures are outside this scope.

Detailed Explanation: Simplify expressions involving matrix addition, subtraction, and scalar multiplication

To simplify an expression with matrices, first check that the matrices have the same dimensions. Then distribute any scalars across every term inside parentheses, combine coefficients of identical matrices, and calculate corresponding entries.

Suppose

A=[12−13],B=[4−205].A=\begin{bmatrix}1&2\\-1&3\end{bmatrix}, \qquad B=\begin{bmatrix}4&-2\\0&5\end{bmatrix}.

Simplify 2A−3(B−A)+B2A-3(B-A)+B.

Distribute −3-3 through the parentheses. Keep the subtraction order in B−AB-A:

2A−3(B−A)+B=2A−3B+3A+B.2A-3(B-A)+B =2A-3B+3A+B.

Combine the coefficients of each matrix:

2A+3A−3B+B=5A−2B.2A+3A-3B+B=5A-2B.

Now multiply each matrix by its scalar and subtract corresponding entries:

5A−2B=[510−515]−[8−4010]=[−314−55].5A-2B = \begin{bmatrix}5&10\\-5&15\end{bmatrix} - \begin{bmatrix}8&-4\\0&10\end{bmatrix} = \begin{bmatrix}-3&14\\-5&5\end{bmatrix}.

So the simplified expression is

[−314−55].\boxed{\begin{bmatrix}-3&14\\-5&5\end{bmatrix}}.

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