Skill: Represent sample spaces using tree diagrams

Explanation and Free Practice Resources

A tree diagram represents the sample space of a finite, multi-step random experiment, with branches showing possible results at each stage and each complete path from the start to an endpoint representing one ordered outcome. The diagram makes clear whether outcomes are exhaustive and nonoverlapping, supports grouping paths into events, and provides a structure for assigning or calculating probabilities. The focus is on simple experiments with a few stages, not generalized combinatorial notation or large, highly dependent sample spaces.

Detailed Explanation: Represent sample spaces using tree diagrams

A tree diagram shows the stages of a random experiment from left to right. Each branch shows one possible result, and each complete path from the start to the end represents one outcome.

Example: A fair coin is tossed twice. Find the sample space and the probability of getting exactly one head.

Step 1: Identify the stages.

There are two stages:

  1. The first coin toss
  2. The second coin toss

For each toss, the possible results are HH (heads) and TT (tails).

Step 2: Draw branches for the first toss.

From the starting point, draw one branch for HH and one branch for TT.

Step 3: Continue each branch for the second toss.

Each first-toss result can be followed by either HH or TT.

Start
├── H
│   ├── H  → HH
│   └── T  → HT
└── T
    ├── H  → TH
    └── T  → TT

Step 4: List the complete paths.

The sample space is

S={HH,HT,TH,TT}.S=\{HH, HT, TH, TT\}.

Each two-letter result is one ordered outcome. For example, HTHT means heads first and tails second, while THTH means tails first and heads second. They are different outcomes because the order is different.

The paths are exhaustive because they include every possible result. They are nonoverlapping because one toss sequence cannot be both HTHT and THTH.

Step 5: Use the tree to find an event.

Exactly one head occurs on the paths

HTandTH.HT \quad \text{and} \quad TH.

Because the coin is fair, each branch has probability 12\frac12. Therefore, each complete path has probability

12×12=14.\frac12 \times \frac12=\frac14.

There are two paths with exactly one head, so

P(exactly one head)=14+14=12.P(\text{exactly one head}) =\frac14+\frac14 =\frac12.

To make a tree diagram, show every possible result at each stage, follow every branch to an endpoint, and use the complete paths as the outcomes in the sample space.

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Probability Sample Space - Definition to Sample Space List


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